To determine the number of prime numbers strictly between 90 and 100, we must examine each integer in that range and check for primality.

The integers strictly between 90 and 100 are:
91, 92, 93, 94, 95, 96, 97, 98, 99.

Let's analyze each number:

1.  **91**: Not prime. It is divisible by 7 and 13 ($7 \times 13 = 91$).
2.  **92**: Not prime. It is an even number greater than 2, so it is divisible by 2.
3.  **93**: Not prime. The sum of its digits is $9 + 3 = 12$, which is divisible by 3, so 93 is divisible by 3 ($3 \times 31 = 93$).
4.  **94**: Not prime. It is an even number, divisible by 2.
5.  **95**: Not prime. It ends in 5, so it is divisible by 5 ($5 \times 19 = 95$).
6.  **96**: Not prime. It is an even number, divisible by 2.
7.  **97**: **Prime**. To verify, we check for divisibility by prime numbers up to $\sqrt{97} \approx 9.8$. The primes to check are 2, 3, 5, and 7.
    *   Not divisible by 2 (it is odd).
    *   Not divisible by 3 (sum of digits $9+7=16$, not divisible by 3).
    *   Not divisible by 5 (does not end in 0 or 5).
    *   Not divisible by 7 ($7 \times 13 = 91$, $7 \times 14 = 98$).
    *   Therefore, 97 is prime.
8.  **98**: Not prime. It is an even number, divisible by 2.
9.  **99**: Not prime. It is divisible by 3, 9, 11, etc. ($9 \times 11 = 99$).

**Conclusion:**

There is only **1** prime number strictly between 90 and 100.

The prime number is:
**97**