To determine how many prime numbers are strictly between 90 and 100, let's examine each integer in that range: **91, 92, 93, 94, 95, 96, 97, 98, 99**.

Here is the step-by-step analysis for each number:

1.  **91**: This number is divisible by 7 ($7 \times 13 = 91$). It is **not prime**.
2.  **92**: This is an even number (divisible by 2). It is **not prime**.
3.  **93**: The sum of its digits is $9 + 3 = 12$, which is divisible by 3. Thus, $93 = 3 \times 31$. It is **not prime**.
4.  **94**: This is an even number (divisible by 2). It is **not prime**.
5.  **95**: This number ends in 5, so it is divisible by 5 ($5 \times 19 = 95$). It is **not prime**.
6.  **96**: This is an even number (divisible by 2). It is **not prime**.
7.  **97**: Let's test for divisibility by primes up to $\sqrt{97}$ (which is approximately 9.8).
    *   Not divisible by 2 (it's odd).
    *   Not divisible by 3 (sum of digits $9+7=16$).
    *   Not divisible by 5 (doesn't end in 0 or 5).
    *   Not divisible by 7 ($7 \times 13 = 91$, $7 \times 14 = 98$).
    *   Therefore, **97 is prime**.
8.  **98**: This is an even number (divisible by 2). It is **not prime**.
9.  **99**: The sum of its digits is $9 + 9 = 18$, which is divisible by 3. Thus, $99 = 9 \times 11$. It is **not prime**.

### Conclusion

There is only **1** prime number strictly between 90 and 100.

The prime number is:
*   **97**